8(y+4)=7y+33

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Solution for 8(y+4)=7y+33 equation: 



8(y+4)=7y+33

We move all terms to the left:

8(y+4)-(7y+33)=0

We multiply parentheses

8y-(7y+33)+32=0

We get rid of parentheses

8y-7y-33+32=0

We add all the numbers together, and all the variables

y-1=0

We move all terms containing y to the left, all other terms to the right

y=1

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