4(4x-1)=2(2x+2+2x)

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Solution for 4(4x-1)=2(2x+2+2x) equation: 



4(4x-1)=2(2x+2+2x)

We move all terms to the left:

4(4x-1)-(2(2x+2+2x))=0

We add all the numbers together, and all the variables

4(4x-1)-(2(4x+2))=0

We multiply parentheses

16x-(2(4x+2))-4=0



We calculate terms in parentheses: -(2(4x+2)), so:

2(4x+2)

We multiply parentheses

8x+4

Back to the equation:

-(8x+4)



We get rid of parentheses

16x-8x-4-4=0

We add all the numbers together, and all the variables

8x-8=0

We move all terms containing x to the left, all other terms to the right

8x=8

x=8/8

x=1

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