b2=61/121

Solution for b2=61/121 equation:

b2=61/121

We move all terms to the left:

b2-(61/121)=0

We add all the numbers together, and all the variables

b2-(+61/121)=0

We add all the numbers together, and all the variables

b^2-(+61/121)=0

We get rid of parentheses

b^2-61/121=0

We multiply all the terms by the denominator


b^2*121-61=0

Wy multiply elements

121b^2-61=0

a = 121; b = 0; c = -61;
Δ = b2-4ac
Δ = 02-4·121·(-61)
Δ = 29524
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{29524}=\sqrt{484*61}=\sqrt{484}*\sqrt{61}=22\sqrt{61}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-22\sqrt{61}}{2*121}=\frac{0-22\sqrt{61}}{242}
=-\frac{22\sqrt{61}}{242}
=-\frac{\sqrt{61}}{11}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+22\sqrt{61}}{2*121}=\frac{0+22\sqrt{61}}{242}
=\frac{22\sqrt{61}}{242}
=\frac{\sqrt{61}}{11}
$