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5x+2(x-3)+2=6x+3(x+2)-4+x
We move all terms to the left:
5x+2(x-3)+2-(6x+3(x+2)-4+x)=0
We multiply parentheses
5x+2x-(6x+3(x+2)-4+x)-6+2=0
We calculate terms in parentheses: -(6x+3(x+2)-4+x), so:We add all the numbers together, and all the variables
6x+3(x+2)-4+x
determiningTheFunctionDomain 6x+3(x+2)+x-4
We add all the numbers together, and all the variables
7x+3(x+2)-4
We multiply parentheses
7x+3x+6-4
We add all the numbers together, and all the variables
10x+2
Back to the equation:
-(10x+2)
7x-(10x+2)-4=0
We get rid of parentheses
7x-10x-2-4=0
We add all the numbers together, and all the variables
-3x-6=0
We move all terms containing x to the left, all other terms to the right
-3x=6
x=6/-3
x=-2
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