-2x-2(3x-5)=6(-3x-2)

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Solution for -2x-2(3x-5)=6(-3x-2) equation: 



-2x-2(3x-5)=6(-3x-2)

We move all terms to the left:

-2x-2(3x-5)-(6(-3x-2))=0

We multiply parentheses

-2x-6x-(6(-3x-2))+10=0



We calculate terms in parentheses: -(6(-3x-2)), so:

6(-3x-2)

We multiply parentheses

-18x-12

Back to the equation:

-(-18x-12)



We add all the numbers together, and all the variables

-8x-(-18x-12)+10=0

We get rid of parentheses

-8x+18x+12+10=0

We add all the numbers together, and all the variables

10x+22=0

We move all terms containing x to the left, all other terms to the right

10x=-22

x=-22/10

x=-2+1/5

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