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5x*x+x-18=0
We add all the numbers together, and all the variables
x+5x*x-18=0
Wy multiply elements
5x^2+x-18=0
a = 5; b = 1; c = -18;
Δ = b2-4ac
Δ = 12-4·5·(-18)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-19}{2*5}=\frac{-20}{10} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+19}{2*5}=\frac{18}{10} =1+4/5 $
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