(b-30)+b+(b+24)=180

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Solution for (b-30)+b+(b+24)=180 equation: 



(b-30)+b+(b+24)=180

We move all terms to the left:

(b-30)+b+(b+24)-(180)=0

We add all the numbers together, and all the variables

b+(b-30)+(b+24)-180=0

We get rid of parentheses

b+b+b-30+24-180=0

We add all the numbers together, and all the variables

3b-186=0

We move all terms containing b to the left, all other terms to the right

3b=186

b=186/3

b=62

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