5x(7-5)+9(6+3x)=3(11x-2)

Solution for 5x(7-5)+9(6+3x)=3(11x-2) equation:

5x(7-5)+9(6+3x)=3(11x-2)

We move all terms to the left:

5x(7-5)+9(6+3x)-(3(11x-2))=0

We add all the numbers together, and all the variables

5x2+9(3x+6)-(3(11x-2))=0

We add all the numbers together, and all the variables

5x^2+9(3x+6)-(3(11x-2))=0

We multiply parentheses

5x^2+27x-(3(11x-2))+54=0


We calculate terms in parentheses: -(3(11x-2)), so:

3(11x-2)

We multiply parentheses

33x-6

Back to the equation:

-(33x-6)


We get rid of parentheses

5x^2+27x-33x+6+54=0

We add all the numbers together, and all the variables

5x^2-6x+60=0

a = 5; b = -6; c = +60;
Δ = b2-4ac
Δ = -62-4·5·60
Δ = -1164
Delta is less than zero, so there is no solution for the equation