17=2+3(t+5)

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Solution for 17=2+3(t+5) equation: 



17=2+3(t+5)

We move all terms to the left:

17-(2+3(t+5))=0



We calculate terms in parentheses: -(2+3(t+5)), so:

2+3(t+5)

determiningTheFunctionDomain
3(t+5)+2

We multiply parentheses

3t+15+2

We add all the numbers together, and all the variables

3t+17

Back to the equation:

-(3t+17)



We get rid of parentheses

-3t-17+17=0

We add all the numbers together, and all the variables

-3t=0

t=0/-3

t=0

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