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5x(5x+12)=-32
We move all terms to the left:
5x(5x+12)-(-32)=0
We add all the numbers together, and all the variables
5x(5x+12)+32=0
We multiply parentheses
25x^2+60x+32=0
a = 25; b = 60; c = +32;
Δ = b2-4ac
Δ = 602-4·25·32
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-20}{2*25}=\frac{-80}{50} =-1+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+20}{2*25}=\frac{-40}{50} =-4/5 $
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