3(x-2)-2(x+1)+5(x-2)=15

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Solution for 3(x-2)-2(x+1)+5(x-2)=15 equation: 



3(x-2)-2(x+1)+5(x-2)=15

We move all terms to the left:

3(x-2)-2(x+1)+5(x-2)-(15)=0

We multiply parentheses

3x-2x+5x-6-2-10-15=0

We add all the numbers together, and all the variables

6x-33=0

We move all terms containing x to the left, all other terms to the right

6x=33

x=33/6

x=5+1/2

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