3(x+2)-3(x+1)+5(x-2)=15

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Solution for 3(x+2)-3(x+1)+5(x-2)=15 equation: 



3(x+2)-3(x+1)+5(x-2)=15

We move all terms to the left:

3(x+2)-3(x+1)+5(x-2)-(15)=0

We multiply parentheses

3x-3x+5x+6-3-10-15=0

We add all the numbers together, and all the variables

5x-22=0

We move all terms containing x to the left, all other terms to the right

5x=22

x=22/5

x=4+2/5

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