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5x(2x+7)=-13-2x
We move all terms to the left:
5x(2x+7)-(-13-2x)=0
We add all the numbers together, and all the variables
5x(2x+7)-(-2x-13)=0
We multiply parentheses
10x^2+35x-(-2x-13)=0
We get rid of parentheses
10x^2+35x+2x+13=0
We add all the numbers together, and all the variables
10x^2+37x+13=0
a = 10; b = 37; c = +13;
Δ = b2-4ac
Δ = 372-4·10·13
Δ = 849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-\sqrt{849}}{2*10}=\frac{-37-\sqrt{849}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+\sqrt{849}}{2*10}=\frac{-37+\sqrt{849}}{20} $
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