4(2x-8)=3(2-3x)-4

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Solution for 4(2x-8)=3(2-3x)-4 equation: 



4(2x-8)=3(2-3x)-4

We move all terms to the left:

4(2x-8)-(3(2-3x)-4)=0

We add all the numbers together, and all the variables

4(2x-8)-(3(-3x+2)-4)=0

We multiply parentheses

8x-(3(-3x+2)-4)-32=0



We calculate terms in parentheses: -(3(-3x+2)-4), so:

3(-3x+2)-4

We multiply parentheses

-9x+6-4

We add all the numbers together, and all the variables

-9x+2

Back to the equation:

-(-9x+2)



We get rid of parentheses

8x+9x-2-32=0

We add all the numbers together, and all the variables

17x-34=0

We move all terms containing x to the left, all other terms to the right

17x=34

x=34/17

x=2

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