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x+3/5x=2160
We move all terms to the left:
x+3/5x-(2160)=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
x*5x-2160*5x+3=0
Wy multiply elements
5x^2-10800x+3=0
a = 5; b = -10800; c = +3;
Δ = b2-4ac
Δ = -108002-4·5·3
Δ = 116639940
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{116639940}=\sqrt{4*29159985}=\sqrt{4}*\sqrt{29159985}=2\sqrt{29159985}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10800)-2\sqrt{29159985}}{2*5}=\frac{10800-2\sqrt{29159985}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10800)+2\sqrt{29159985}}{2*5}=\frac{10800+2\sqrt{29159985}}{10} $
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