(3/2)x-1=(4/5)x+6

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Solution for (3/2)x-1=(4/5)x+6 equation:



(3/2)x-1=(4/5)x+6
We move all terms to the left:
(3/2)x-1-((4/5)x+6)=0
Domain of the equation: 2)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 5)x+6)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+3/2)x-((+4/5)x+6)-1=0
We multiply parentheses
3x^2-((+4/5)x+6)-1=0
We multiply all the terms by the denominator
3x^2*5)x+6)-((-1*5)x+6)+4=0
We add all the numbers together, and all the variables
3x^2*5)x+6)-((-5)x+6)+4=0
Wy multiply elements
15x^3-5)x+6)+4=0
We do not support expression: x^3

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