(3y+5)=3(5y+1/3)

Solution for (3y+5)=3(5y+1/3) equation:

(3y+5)=3(5y+1/3)

We move all terms to the left:

(3y+5)-(3(5y+1/3))=0

We add all the numbers together, and all the variables

(3y+5)-(3(+5y+1/3))=0

We get rid of parentheses

3y-(3(+5y+1/3))+5=0

We multiply all the terms by the denominator


3y*3))-(3(+5y+1+5*3))=0

We add all the numbers together, and all the variables

3y*3))-(3(5y+16))=0

We add all the numbers together, and all the variables

3y*3))-(3(5y=0

Wy multiply elements

9y^2=0

a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{18}=0$