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5x(10x-30)=900
We move all terms to the left:
5x(10x-30)-(900)=0
We multiply parentheses
50x^2-150x-900=0
a = 50; b = -150; c = -900;
Δ = b2-4ac
Δ = -1502-4·50·(-900)
Δ = 202500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{202500}=450$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-450}{2*50}=\frac{-300}{100} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+450}{2*50}=\frac{600}{100} =6 $
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