3(n-4)+2(5n-5)=5(n+2)+16

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Solution for 3(n-4)+2(5n-5)=5(n+2)+16 equation: 



3(n-4)+2(5n-5)=5(n+2)+16

We move all terms to the left:

3(n-4)+2(5n-5)-(5(n+2)+16)=0

We multiply parentheses

3n+10n-(5(n+2)+16)-12-10=0



We calculate terms in parentheses: -(5(n+2)+16), so:

5(n+2)+16

We multiply parentheses

5n+10+16

We add all the numbers together, and all the variables

5n+26

Back to the equation:

-(5n+26)



We add all the numbers together, and all the variables

13n-(5n+26)-22=0

We get rid of parentheses

13n-5n-26-22=0

We add all the numbers together, and all the variables

8n-48=0

We move all terms containing n to the left, all other terms to the right

8n=48

n=48/8

n=6

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