8=(x+2)(x-2)

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Solution for 8=(x+2)(x-2) equation: 



8=(x+2)(x-2)

We move all terms to the left:

8-((x+2)(x-2))=0

We use the square of the difference formula

x^2+4+8=0

We add all the numbers together, and all the variables

x^2+12=0

a = 1; b = 0; c = +12;
Δ = b2-4ac
Δ = 02-4·1·12
Δ = -48
Delta is less than zero, so there is no solution for the equation

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