5v2-18v=13=4

Solution for 5v2-18v=13=4 equation:

5v^2-18v=13=4

We move all terms to the left:

5v^2-18v-(13)=0

a = 5; b = -18; c = -13;
Δ = b2-4ac
Δ = -182-4·5·(-13)
Δ = 584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{584}=\sqrt{4*146}=\sqrt{4}*\sqrt{146}=2\sqrt{146}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{146}}{2*5}=\frac{18-2\sqrt{146}}{10}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{146}}{2*5}=\frac{18+2\sqrt{146}}{10}
$