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5(e+6)=2-(-5e-28)
We move all terms to the left:
5(e+6)-(2-(-5e-28))=0
We multiply parentheses
5e-(2-(-5e-28))+30=0
We calculate terms in parentheses: -(2-(-5e-28)), so:We get rid of parentheses
2-(-5e-28)
determiningTheFunctionDomain -(-5e-28)+2
We get rid of parentheses
5e+28+2
We add all the numbers together, and all the variables
5e+30
Back to the equation:
-(5e+30)
5e-5e-30+30=0
We add all the numbers together, and all the variables
=0
e=0/1
e=0
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