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5t-8=4-(5t-8)
We move all terms to the left:
5t-8-(4-(5t-8))=0
We calculate terms in parentheses: -(4-(5t-8)), so:We get rid of parentheses
4-(5t-8)
determiningTheFunctionDomain -(5t-8)+4
We get rid of parentheses
-5t+8+4
We add all the numbers together, and all the variables
-5t+12
Back to the equation:
-(-5t+12)
5t+5t-12-8=0
We add all the numbers together, and all the variables
10t-20=0
We move all terms containing t to the left, all other terms to the right
10t=20
t=20/10
t=2
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