4(z-5)+2=4z=4z-18

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Solution for 4(z-5)+2=4z=4z-18 equation: 



4(z-5)+2=4z=4z-18

We move all terms to the left:

4(z-5)+2-(4z)=0

We add all the numbers together, and all the variables

-4z+4(z-5)+2=0

We multiply parentheses

-4z+4z-20+2=0

We add all the numbers together, and all the variables

-18!=0

There is no solution for this equation

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