2(c-5)-(3c+4)=7

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Solution for 2(c-5)-(3c+4)=7 equation: 



2(c-5)-(3c+4)=7

We move all terms to the left:

2(c-5)-(3c+4)-(7)=0

We multiply parentheses

2c-(3c+4)-10-7=0

We get rid of parentheses

2c-3c-4-10-7=0

We add all the numbers together, and all the variables

-1c-21=0

We move all terms containing c to the left, all other terms to the right

-c=21

c=21/-1

c=-21

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