5r+6+4r-6=-2(r-7)-3(7r-6)

Solution for 5r+6+4r-6=-2(r-7)-3(7r-6) equation:

5r+6+4r-6=-2(r-7)-3(7r-6)

We move all terms to the left:

5r+6+4r-6-(-2(r-7)-3(7r-6))=0

We add all the numbers together, and all the variables

9r-(-2(r-7)-3(7r-6))=0


We calculate terms in parentheses: -(-2(r-7)-3(7r-6)), so:

-2(r-7)-3(7r-6)

We multiply parentheses

-2r-21r+14+18

We add all the numbers together, and all the variables

-23r+32

Back to the equation:

-(-23r+32)


We get rid of parentheses

9r+23r-32=0

We add all the numbers together, and all the variables

32r-32=0

We move all terms containing r to the left, all other terms to the right

32r=32

r=32/32

r=1