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5k^2=60-20k
We move all terms to the left:
5k^2-(60-20k)=0
We add all the numbers together, and all the variables
5k^2-(-20k+60)=0
We get rid of parentheses
5k^2+20k-60=0
a = 5; b = 20; c = -60;
Δ = b2-4ac
Δ = 202-4·5·(-60)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-40}{2*5}=\frac{-60}{10} =-6 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+40}{2*5}=\frac{20}{10} =2 $
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