6(p+2)=4(p-1)

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Solution for 6(p+2)=4(p-1) equation: 



6(p+2)=4(p-1)

We move all terms to the left:

6(p+2)-(4(p-1))=0

We multiply parentheses

6p-(4(p-1))+12=0



We calculate terms in parentheses: -(4(p-1)), so:

4(p-1)

We multiply parentheses

4p-4

Back to the equation:

-(4p-4)



We get rid of parentheses

6p-4p+4+12=0

We add all the numbers together, and all the variables

2p+16=0

We move all terms containing p to the left, all other terms to the right

2p=-16

p=-16/2

p=-8

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