2(x-6)=3(x-4)-x

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Solution for 2(x-6)=3(x-4)-x equation: 



2(x-6)=3(x-4)-x

We move all terms to the left:

2(x-6)-(3(x-4)-x)=0

We multiply parentheses

2x-(3(x-4)-x)-12=0



We calculate terms in parentheses: -(3(x-4)-x), so:

3(x-4)-x

We add all the numbers together, and all the variables

-1x+3(x-4)

We multiply parentheses

-1x+3x-12

We add all the numbers together, and all the variables

2x-12

Back to the equation:

-(2x-12)



We get rid of parentheses

2x-2x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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