If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5k^2-34k+24=0
a = 5; b = -34; c = +24;
Δ = b2-4ac
Δ = -342-4·5·24
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-26}{2*5}=\frac{8}{10} =4/5 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+26}{2*5}=\frac{60}{10} =6 $
| (2x+3)+(5x+3)=90 | | 9(x-2)=7x+5 | | (x-5)(x+10)=0 | | (1/2)d-3=4 | | 4x+(2x+12)=90 | | x/7-9=5/14 | | a^2-10-24=0 | | 4/5x+7/10=13/15x-3/5 | | 5x+7=2(3x-4) | | x-50=5(2x+3)-11 | | w+(−4)=37 | | 3x^2+7x-208=0 | | Y=2y/2+6/2 | | 7g=-12 | | 5b=99 | | -1c-2=4 | | 6x+-6x=-2 | | 3x+32=18 | | x=3,14x^2 | | 2x(x+-5=6x+2 | | 5x-4=(4x+1)/1-3x+10/2 | | 5(y-8)+8y=-27 | | -10=b/5 | | 8+5x=2+6x | | 7x+13x-1=4(5x+4) | | 14t-17=6t+4 | | 36=5(x+5)+6x | | (4x+2)-(2x-5)=0 | | 5x+2/5-3x-1/4=x-3/5 | | 4x^2 =3x-2 | | 4(u-4)+3u=5 | | -2r-6-14=-13+6 |