5k+4k+6-5=4(2k-2)

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Solution for 5k+4k+6-5=4(2k-2) equation: 



5k+4k+6-5=4(2k-2)

We move all terms to the left:

5k+4k+6-5-(4(2k-2))=0

We add all the numbers together, and all the variables

9k-(4(2k-2))+1=0



We calculate terms in parentheses: -(4(2k-2)), so:

4(2k-2)

We multiply parentheses

8k-8

Back to the equation:

-(8k-8)



We get rid of parentheses

9k-8k+8+1=0

We add all the numbers together, and all the variables

k+9=0

We move all terms containing k to the left, all other terms to the right

k=-9

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