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2x(3x+1)=2x(1)
We move all terms to the left:
2x(3x+1)-(2x(1))=0
determiningTheFunctionDomain 2x(3x+1)-2x1=0
We add all the numbers together, and all the variables
-2x+2x(3x+1)=0
We multiply parentheses
6x^2-2x+2x=0
We add all the numbers together, and all the variables
6x^2=0
a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{12}=0$
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