0=200t-16t2

Solution for 0=200t-16t2 equation:

0=200t-16t^2

We move all terms to the left:

0-(200t-16t^2)=0

We add all the numbers together, and all the variables

-(200t-16t^2)=0

We get rid of parentheses

16t^2-200t=0

a = 16; b = -200; c = 0;
Δ = b2-4ac
Δ = -2002-4·16·0
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40000}=200$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-200)-200}{2*16}=\frac{0}{32}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-200)+200}{2*16}=\frac{400}{32}
=12+1/2
$