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5c-3-4c=2(c+3)+10
We move all terms to the left:
5c-3-4c-(2(c+3)+10)=0
We add all the numbers together, and all the variables
c-(2(c+3)+10)-3=0
We calculate terms in parentheses: -(2(c+3)+10), so:We get rid of parentheses
2(c+3)+10
We multiply parentheses
2c+6+10
We add all the numbers together, and all the variables
2c+16
Back to the equation:
-(2c+16)
c-2c-16-3=0
We add all the numbers together, and all the variables
-1c-19=0
We move all terms containing c to the left, all other terms to the right
-c=19
c=19/-1
c=-19
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