4(x+3)=21+x+1

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Solution for 4(x+3)=21+x+1 equation: 



4(x+3)=21+x+1

We move all terms to the left:

4(x+3)-(21+x+1)=0

We add all the numbers together, and all the variables

4(x+3)-(x+22)=0

We multiply parentheses

4x-(x+22)+12=0

We get rid of parentheses

4x-x-22+12=0

We add all the numbers together, and all the variables

3x-10=0

We move all terms containing x to the left, all other terms to the right

3x=10

x=10/3

x=3+1/3

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