3(r-12)=6

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Solution for 3(r-12)=6 equation: 



3(r-12)=6

We move all terms to the left:

3(r-12)-(6)=0

We multiply parentheses

3r-36-6=0

We add all the numbers together, and all the variables

3r-42=0

We move all terms containing r to the left, all other terms to the right

3r=42

r=42/3

r=14

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