-2(f+2)-4=2(2f-4)

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Solution for -2(f+2)-4=2(2f-4) equation: 



-2(f+2)-4=2(2f-4)

We move all terms to the left:

-2(f+2)-4-(2(2f-4))=0

We multiply parentheses

-2f-(2(2f-4))-4-4=0



We calculate terms in parentheses: -(2(2f-4)), so:

2(2f-4)

We multiply parentheses

4f-8

Back to the equation:

-(4f-8)



We add all the numbers together, and all the variables

-2f-(4f-8)-8=0

We get rid of parentheses

-2f-4f+8-8=0

We add all the numbers together, and all the variables

-6f=0

f=0/-6

f=0

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