5c+1=4(2+c)

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Solution for 5c+1=4(2+c) equation: 



5c+1=4(2+c)

We move all terms to the left:

5c+1-(4(2+c))=0

We add all the numbers together, and all the variables

5c-(4(c+2))+1=0



We calculate terms in parentheses: -(4(c+2)), so:

4(c+2)

We multiply parentheses

4c+8

Back to the equation:

-(4c+8)



We get rid of parentheses

5c-4c-8+1=0

We add all the numbers together, and all the variables

c-7=0

We move all terms containing c to the left, all other terms to the right

c=7

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