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5(5x-x)=4(x-5)
We move all terms to the left:
5(5x-x)-(4(x-5))=0
We add all the numbers together, and all the variables
5(+4x)-(4(x-5))=0
We multiply parentheses
20x-(4(x-5))=0
We calculate terms in parentheses: -(4(x-5)), so:We get rid of parentheses
4(x-5)
We multiply parentheses
4x-20
Back to the equation:
-(4x-20)
20x-4x+20=0
We add all the numbers together, and all the variables
16x+20=0
We move all terms containing x to the left, all other terms to the right
16x=-20
x=-20/16
x=-1+1/4
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