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5b+12=1/2(10b+24)
We move all terms to the left:
5b+12-(1/2(10b+24))=0
Domain of the equation: 2(10b+24))!=0We multiply all the terms by the denominator
b∈R
5b*2(10b+24))-(1+12*2(10b+24))=0
Wy multiply elements
10b^2(1+24b(1=0
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