(1n+8=)+(1n-12=)

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Solution for (1n+8=)+(1n-12=) equation: 



(1n+8=)+(1n-12=)

We move all terms to the left:

(1n+8-()+(1n-12)=0

We add all the numbers together, and all the variables

(1n+8-()+(n-12)=0



We calculate terms in parentheses: +(1n+8-()+(n-12), so:

1n+8-()+(n-12

determiningTheFunctionDomain
1n+(n-12+8-()

We add all the numbers together, and all the variables

n+(n-12+8-()



We calculate terms in parentheses: +(n-12+8-(), so:

n-12+8-(

We add all the numbers together, and all the variables

n

Back to the equation:

+(n)



We add all the numbers together, and all the variables

2n

Back to the equation:

+(2n)



n=0/2

n=0

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