(5-2z)=20-2(z-1)

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Solution for (5-2z)=20-2(z-1) equation: 



(5-2z)=20-2(z-1)

We move all terms to the left:

(5-2z)-(20-2(z-1))=0

We add all the numbers together, and all the variables

(-2z+5)-(20-2(z-1))=0

We get rid of parentheses

-2z-(20-2(z-1))+5=0



We calculate terms in parentheses: -(20-2(z-1)), so:

20-2(z-1)

determiningTheFunctionDomain
-2(z-1)+20

We multiply parentheses

-2z+2+20

We add all the numbers together, and all the variables

-2z+22

Back to the equation:

-(-2z+22)



We get rid of parentheses

-2z+2z-22+5=0

We add all the numbers together, and all the variables

-17!=0

There is no solution for this equation

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