5a2+5a-3=0

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Solution for 5a2+5a-3=0 equation: 



5a^2+5a-3=0

a = 5; b = 5; c = -3;
Δ = b2-4ac
Δ = 52-4·5·(-3)
Δ = 85
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{85}}{2*5}=\frac{-5-\sqrt{85}}{10}
$


$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{85}}{2*5}=\frac{-5+\sqrt{85}}{10}
$

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