4(d-4)=2=3(d+1)

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Solution for 4(d-4)=2=3(d+1) equation: 



4(d-4)=2=3(d+1)

We move all terms to the left:

4(d-4)-(2)=0

We multiply parentheses

4d-16-2=0

We add all the numbers together, and all the variables

4d-18=0

We move all terms containing d to the left, all other terms to the right

4d=18

d=18/4

d=4+1/2

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