5(x-2)+2x=(x+4)-38

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Solution for 5(x-2)+2x=(x+4)-38 equation: 



5(x-2)+2x=(x+4)-38

We move all terms to the left:

5(x-2)+2x-((x+4)-38)=0

We add all the numbers together, and all the variables

2x+5(x-2)-((x+4)-38)=0

We multiply parentheses

2x+5x-((x+4)-38)-10=0



We calculate terms in parentheses: -((x+4)-38), so:

(x+4)-38

We get rid of parentheses

x+4-38

We add all the numbers together, and all the variables

x-34

Back to the equation:

-(x-34)



We add all the numbers together, and all the variables

7x-(x-34)-10=0

We get rid of parentheses

7x-x+34-10=0

We add all the numbers together, and all the variables

6x+24=0

We move all terms containing x to the left, all other terms to the right

6x=-24

x=-24/6

x=-4

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