5a+(4-a)=9(a-6)

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Solution for 5a+(4-a)=9(a-6) equation: 



5a+(4-a)=9(a-6)

We move all terms to the left:

5a+(4-a)-(9(a-6))=0

We add all the numbers together, and all the variables

5a+(-1a+4)-(9(a-6))=0

We get rid of parentheses

5a-1a-(9(a-6))+4=0



We calculate terms in parentheses: -(9(a-6)), so:

9(a-6)

We multiply parentheses

9a-54

Back to the equation:

-(9a-54)



We add all the numbers together, and all the variables

4a-(9a-54)+4=0

We get rid of parentheses

4a-9a+54+4=0

We add all the numbers together, and all the variables

-5a+58=0

We move all terms containing a to the left, all other terms to the right

-5a=-58

a=-58/-5

a=11+3/5

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