(2x+13)/2x=(x-2)/(x-5)

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Solution for (2x+13)/2x=(x-2)/(x-5) equation: 



(2x+13)/2x=(x-2)/(x-5)

We move all terms to the left:

(2x+13)/2x-((x-2)/(x-5))=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R





Domain of the equation: (x-5))!=0

x∈R



We calculate fractions


-8x^2)+(-((x-2)*2x)/(-8x^2)+((2x+13)*(x-5)))/(=0



We calculate terms in parentheses: -((x-2)*2x)/(-8x^2), so:

(x-2)*2x)/(-8x^2

determiningTheFunctionDomain
-8x^2+(x-2)*2x)/(

We multiply all the terms by the denominator


-8x^2*(+(x-2)*2x)

Back to the equation:

-(-8x^2*(+(x-2)*2x))



We multiply all the terms by the denominator


()*(-((-8x^2*(+(x-2)*2x)))*(+((2x+13)*(x-5)))-8x^2=0

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