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6(t-5)=5(t+1)
We move all terms to the left:
6(t-5)-(5(t+1))=0
We multiply parentheses
6t-(5(t+1))-30=0
We calculate terms in parentheses: -(5(t+1)), so:We get rid of parentheses
5(t+1)
We multiply parentheses
5t+5
Back to the equation:
-(5t+5)
6t-5t-5-30=0
We add all the numbers together, and all the variables
t-35=0
We move all terms containing t to the left, all other terms to the right
t=35
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