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3z+4/2z+5=2
We move all terms to the left:
3z+4/2z+5-(2)=0
Domain of the equation: 2z!=0We add all the numbers together, and all the variables
z!=0/2
z!=0
z∈R
3z+4/2z+3=0
We multiply all the terms by the denominator
3z*2z+3*2z+4=0
Wy multiply elements
6z^2+6z+4=0
a = 6; b = 6; c = +4;
Δ = b2-4ac
Δ = 62-4·6·4
Δ = -60
Delta is less than zero, so there is no solution for the equation
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