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5X^2-20X-60=0
a = 5; b = -20; c = -60;
Δ = b2-4ac
Δ = -202-4·5·(-60)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-40}{2*5}=\frac{-20}{10} =-2 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+40}{2*5}=\frac{60}{10} =6 $
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